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- Here is a comparison matrix which shows a case in which
- it is possible for the forward and backward scan in `diag'
- to meet along a nonzero length of diagonal simultaneous
- (so that bdiag[d] and fdiag[d] are not equal)
- even though there is no snake on that diagonal at the meeting point.
-
-
- 85 1 1 1 159 1 1 17
- 1 2 3 4
- 60
- 1 2
- 1
- 2 2 3 4
- 71
- 3 3 4 5
- 85
- 4 3 4 5
- 17
- 5 4 5
- 1
- 6 4 5 6
- 183
- 7 5 6 7
- 10
- 8 6 7
- 1
- 9 6 7 8
- 12
- 7 8 9 10
- 13
- 10 8 9 10
- 14
- 10 9 10
- 17
- 10 10
- 1
- 10 9 10
- 1
- 8 10 10 10
- 183
- 8 7 9 9 9
- 10
- 7 6 8 9 8 8
- 1
- 6 5 7 7
- 1
- 5 6 6
- 1
- 5 5 5
- 50
- 5 4 4 4
- 1
- 4 3 3
- 85
- 5 4 3 2 2
- 1
- 2 1
- 17
- 5 4 3 2 1 1
- 1
- 1 0
- 85 1 1 1 159 1 1 17
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